Arrange the following bonds according to their

Question:

Arrange the following bonds according to their average bond energies in descending order :

$\mathrm{C}-\mathrm{Cl}, \mathrm{C}-\mathrm{Br}, \mathrm{C}-\mathrm{F}, \mathrm{C}-\mathrm{I}$

  1. $\mathrm{C}-\mathrm{I}>\mathrm{C}-\mathrm{Br}>\mathrm{C}-\mathrm{Cl}>\mathrm{C}-\mathrm{F}$

  2. $\mathrm{C}-\mathrm{Br}>\mathrm{C}-\mathrm{I}>\mathrm{C}-\mathrm{Cl}>\mathrm{C}-\mathrm{F}$

  3. $\mathrm{C}-\mathrm{F}>\mathrm{C}-\mathrm{Cl}>\mathrm{C}-\mathrm{Br}>\mathrm{C}-\mathrm{I}$

  4. $\mathrm{C}-\mathrm{Cl}>\mathrm{C}-\mathrm{Br}>\mathrm{C}-\mathrm{I}>\mathrm{C}-\mathrm{F}$


Correct Option: , 3

Solution:

Bond length order in carbon halogen bonds are in the order of $\mathrm{C}-\mathrm{F}<\mathrm{C}-\mathrm{Cl}<\mathrm{C}-\mathrm{Br}<\mathrm{C}-\mathrm{I}$

Hence, Bond energy order

$\mathrm{C}-\mathrm{F}>\mathrm{C}-\mathrm{Cl}>\mathrm{C}-\mathrm{Br}>\mathrm{C}-\mathrm{I}$

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