Calculate the maximum kinetic energy of the beta particle emitted in the following decay scheme:

Question:

Calculate the maximum kinetic energy of the beta particle emitted in the following decay scheme:

$12 \mathrm{~N} \rightarrow{ }^{12} \mathrm{C}^{*}+\mathrm{e}^{+}+\mathrm{V}$

${ }^{12} \mathrm{C}^{*} \rightarrow{ }^{12} \mathrm{C}+\gamma(4.43 \mathrm{MeV})$

The atomic mass of ${ }^{12} \mathrm{~N}$ is $12.018613 \mathrm{u}$

Solution:

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