Calculate the osmotic pressure in pascals exerted by a solution prepared by

Question:

Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0 g of polymer of molar mass 185,000 in 450 mL of water at 37°C.

Solution:

It is given that:

Volume of water, V = 450 mL = 0.45 L

Temperature, T = (37 + 273)K = 310 K

Number of moles of the polymer, $n=\frac{1}{185000} \mathrm{~mol}$

We know that:

Osmotic pressure, $\pi=\frac{n}{V} \mathrm{R} T$

$=\frac{1}{185000} \mathrm{~mol} \times \frac{1}{0.45 \mathrm{~L}} \times 8.314 \times 10^{3} \mathrm{~Pa} \mathrm{~L} \mathrm{~K}^{-1} \mathrm{~mol}^{-1} \times 310 \mathrm{~K}$

= 30.98 Pa

 

= 31 Pa (approximately)

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