Calculate the potential of hydrogen electrode in contact

Question:

Calculate the potential of hydrogen electrode in contact with a solution whose pH is 10.

Solution:

For hydrogen electrode, $\mathrm{H}^{+}+\mathrm{e}^{-} \longrightarrow \frac{1}{2} \mathrm{H}_{2}$, it is given that $\mathrm{pH}=10$

[H+] = 10−10 M

Now, using Nernst equation:

= −0.0591 log 1010

= −0.591 V