Question:
Complete the following table:
Solution:
If initial velocity is $\mathrm{u}$ and deacceleration is $-\mathrm{a}$ then braking distance
$v^{2}=u^{2}+2 a s$
$0^{2}=u^{2}-2 a S$
$\mathrm{S}_{\mathrm{b}}=\frac{\mathrm{u} 2}{2 \mathrm{a}}$ (Braking distance)
$\mathrm{S}_{\mathrm{R}}=\mathrm{u} \times \mathrm{t}_{\mathrm{R}}$ (Reaction distance)
Total distance $=\mathrm{S}_{\mathrm{b}}+\mathrm{S}_{\mathrm{R}}$
Solve table with given values and above formulas