Consider a binary operation on


Consider a binary operation on $\mathrm{Q}-\{1\}$, defined by $\mathrm{a} * \mathrm{~b}=\mathrm{a}+\mathrm{b}-\mathrm{ab}$.

(i) Find the identity element in $\mathrm{Q}-\{1\}$.

(ii) Show that each $a \in Q-\{1\}$ has its inverse.



(i) For a binary operation $*$, e identity element exists if $a * e=e^{*} a=a .$ As $a * b=a+b-a b$

$a * e=a+e-a e(1)$

$e^{*} a=e+a-e a(2)$

using $a^{*} e=a$

$a+e-a e=a$

$e-a e=0$


either $e=0$ or $a=1$ as operation is on $Q$ excluding 1 so $a \neq 1$, hence $e=0$.

So identity element $e=0$.

(ii) for a binary operation $*$ if e is identity element then it is invertible with respect to $*$ if for an element $b, a^{*} b=e=b^{*} a$ where $b$ is called inverse of $*$ and denoted by $a^{-1}$.

$a * b=0$

$a+b-a b=0$


$\mathrm{b}=\frac{-\mathrm{a}}{(1-\mathrm{a})} \Rightarrow \frac{\mathrm{a}}{(\mathrm{a}-1)}$



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