Question:
Consider a cell given below
Cu|Cu2+|| Cl—|Cl2, Pt
Write the reactions that occur at anode and cathode.
Solution:
Galvanic cell: Cu|Cu2+|| Cl—|Cl2, Pt
Anode- Oxidation half-cell: Cu(s) → Cu2+ + 2e-
Cathode- Reduction half-cell: Cl2(g)+ 2e-→ 2Cl-
Thus, Cu is anode as it is getting oxidised.