Consider a cell given below

Question:

Consider a cell given below

Cu|Cu2+|| Cl—|Cl2, Pt

Write the reactions that occur at anode and cathode.

Solution:

Galvanic cell: Cu|Cu2+|| Cl—|Cl2, Pt

Anode- Oxidation half-cell: Cu(s) → Cu2+ + 2e-

Cathode- Reduction half-cell: Cl2(g)+ 2e-→ 2Cl-

Thus, Cu is anode as it is getting oxidised.

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