Consider f : R → R given by f(x) = 4x + 3.


Consider $f: R \rightarrow R$ given by $f(x)=4 x+3$. Show that $f$ is invertible. Find the inverse of $f$.


Injectivity of $f$ :

Let $x$ and $y$ be two elements of domain $(R)$, such that


$\Rightarrow 4 x+3=4 y+3$

$\Rightarrow 4 x=4 y$

$\Rightarrow x=y$

So, $f$ is one-one.

Surjectivity of $f$ :

Let $y$ be in the co-domain $(R)$, such that $f(x)=y$.

$\Rightarrow 4 x+3=y$

$\Rightarrow 4 x=y-3$

$\Rightarrow x=\frac{y-3}{4} \in R($ Domain $)$

$\Rightarrow f$ is onto.

So, $f$ is a bijection and, hence, is invertible.

Finding $f^{-1}$ :

Let $f^{-1}(x)=y$ $\ldots(1)$

$\Rightarrow x=f(y)$

$\Rightarrow x=4 y+3$

$\Rightarrow x-3=4 y$

$\Rightarrow y=\frac{x-3}{4}$

So, $f^{-1}(x)=\frac{x-3}{4} \quad[$ from (1) $]$


Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now