Consider the above reaction where


Consider the above reaction where $6.1 \mathrm{~g}$ of benzoic acid is used to get $7.8 \mathrm{~g}$ of $\mathrm{m}$-bromo

benzoic acid. The percentage yield of the product is _______________ . (Round off to the Nearest integer)

[Given : Atomic masses : $\mathrm{C}=12.0 \mathrm{u}, \mathrm{H}: 1.0 \mathrm{u}$,$\mathrm{O}: 16.0 \mathrm{u}, \mathrm{Br}=80.0 \mathrm{u}]$



Moles of Benzoic acid $=\frac{6.1}{122}=$ moles of $\mathrm{m}$-bromobenzoic acid So, weight thel mobenzoic acid

$=\frac{6.1}{122} \times 201 \mathrm{gm}$

$=10.05 \mathrm{gm}$

$\%$ yield $=\frac{\text { Actual weight }}{\text { Theoretical weight }} \times 100$

$=\frac{7.8}{10.05} \times 100$

$=77.61 \%$

Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now