# Consider the following reduction processes :

Question:

Consider the following reduction processes :

$\mathrm{Zn}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Zn}(\mathrm{s}) ; \mathrm{E}^{\circ}=-0.76 \mathrm{~V}$

$\mathrm{Ca}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Ca}(\mathrm{s}) ; \mathrm{E}^{\circ}=-2.87 \mathrm{~V}$

$\mathrm{Mg}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Mg}(\mathrm{s}) ; \mathrm{E}^{\circ}=-2.36 \mathrm{~V}$

$\mathrm{Ni}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Ni}(\mathrm{s}) ; \mathrm{E}^{\circ}=-0.25 \mathrm{~V}$

The reducing power of the metals increases in the order:

1. $\mathrm{Ca}<\mathrm{Zn}<\mathrm{Mg}<\mathrm{Ni}$

2. $\mathrm{Ni}<\mathrm{Zn}<\mathrm{Mg}<\mathrm{Ca}$

3. $\mathrm{Zn}<\mathrm{Mg}<\mathrm{Ni}<\mathrm{Ca}$

4. $\mathrm{Ca}<\mathrm{Mg}<\mathrm{Zn}<\mathrm{Ni}$

Correct Option: , 2

Solution:

Higher the oxidation potential better will be reducing power.