Question:
Consider the three planes
$P_{1}: 3 x+15 y+21 z=9$
$P_{2}: x-3 y-z=5$, and
$P_{3}: 2 x+10 y+14 z=5$
Then, which one of the following is true?
Correct Option: 1
Solution:
$P_{1}=x+5 y+7 z=3$
$P_{2}=x-3 y-z=5$
$P_{3}=x+5 y+7 z=5 / 2$
$\Rightarrow P_{1} \| P_{3}$
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