Question:
Consider two satellites $S_{1}$ and $S_{2}$ with periods of revolution $1 \mathrm{hr}$. and $8 \mathrm{hr}$. respectively revolving around a planet in circular orbits. The ratio of angular velocity of satellite $S_{1}$ to the angular velocity of satellites $S_{2}$ is :
Correct Option: 1
Solution:
$\frac{\mathrm{T}_{1}}{\mathrm{~T}_{2}}=\frac{1}{8}$
$\frac{2 \pi / \omega_{1}}{2 \pi / \omega_{2}}=\frac{1}{8}$
$\frac{\omega_{1}}{\omega_{2}}=\frac{8}{1}$
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