Question:
Construct a quadrilateral PQRS in which PQ = 4.2 cm, ∠PQR = 60°, ∠QPS = 120°, QR = 5 cm and PS = 6 cm.
Solution:
Steps of construction:
Step 1: Take $P Q=4.2 \mathrm{~cm}$
Step 2: Make $\angle X P Q=120^{\circ}, \angle Y Q P=60^{\circ}$
Step 3: Cut an arc of length 5 cm from point Q. Name that point as R.
Step 4: From P, make an arc of length 6 cm. Name that point as S.
Step 5: Join P and S.
Thus, PQRS is a quadrilateral..png)