Construct a triangle of sides 4 cm, 5 cm and 6 cm and then a triangle similar to it whose sides are (2/3) of the corresponding sides of it.
Given that
Construct a triangle of sides $4 \mathrm{~cm}, 5 \mathrm{~cm}$ and $6 \mathrm{~cm}$ and then a triangle similar to it whose sides are $(2 / 3)$ of the corresponding sides of it.
We follow the following steps to construct the given
Step of construction
Step: I- First of all we draw a line segment.
Step: II- With A as centre and radius, draw an arc.
Step: III- With B as centre and radius, draw an arc, intersecting the arc drawn in step II at C.
Step: IV- Joins AC and BC to obtain.
Step: V- Below AB, makes an acute angle.
Step: VI- Along AX, mark off three points such that
Step: VII- Join.
Step: VIII- Since we have to construct a triangle each of whose sides is two-third of the corresponding sides of.
So, we take two parts out of three equal parts on AX from point draw and meeting AB at C’.
Step: IX- From B’ draw and meeting AC at C’
Thus, is the required triangle, each of whose sides is two third of the corresponding sides of.
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.