CsCl crystallises in body centred cubic lattice. if ‘a’ is its edge
Question:

CsCl crystallises in body centred cubic lattice. if ‘a’ is its edge length then which of the

following expression is correct :

  1. $\mathrm{r}_{\mathrm{Cs}^{+}}+\mathrm{r}_{\mathrm{Cl}^{-}}=\frac{\sqrt{3}}{2} \mathrm{a}$

  2. $\mathrm{r}_{\mathrm{cs}^{+}}+\mathrm{r}_{\mathrm{Cl}^{-}}=\sqrt{3 \mathrm{a}}$

  3. $\mathrm{r}_{\mathrm{Cs}^{+}}+\mathrm{r}_{\mathrm{Cl}^{-}}=3 \mathrm{a}$

  4. $\mathrm{r}_{\mathrm{Cs}^{+}}+\mathrm{r}_{\mathrm{Cl}^{-}}=\frac{3 \mathrm{a}}{2}$


Correct Option: 1

Solution:

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