**Question:**

Divide a line segment of length 14 cm internally in the ratio 2 : 5. Also, justify your construction.

**Solution:**

Given that

Determine a point which divides a line segment of lengthinternally in the ratio of.

We follow the following steps to construct the given

Step of construction

Step: I-First of all we draw a line segment.

Step: II- We draw a ray making an acute anglewith.

Step: III- Draw a ray parallel to *AX* by making an acute angle.

Step IV- Mark of two points on and three points on in such a way that.

Step: V- Joins and this line intersects at a point *P*.

Thus, *P* is the point dividing internally in the ratio of

Justification:

In $\triangle A A_{2} P$ and $\triangle B B_{5} P$, we have

$\angle A_{2} A P=\angle P B B_{5}[\angle A B Y=\angle B A X]$

And $\angle A P A_{2}=\angle B P B_{5}$ [Vertically opposite angle]

So, *AA* similarity criterion, we have

$\triangle A A_{2} P \approx \Delta B B_{5} P$

$\frac{A A_{2}}{B B_{5}}=\frac{A P}{B P}$

$\frac{A P}{B P}=\frac{2}{5}$

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