Evaluate the following integrals:

Question:

Evaluate: $\int \frac{\log x^{x}}{x} d x$

Solution:

given $\int \frac{\log x^{x}}{x} d x$

$=\int \frac{x \log x}{x} d x$

$=\int \log x$

$=x \log x-x+c$

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