Evaluate the following integrals:

Question:

Evaluate: $\int \sec ^{2}(7-4 x) d x$

Solution:

let $7-4 x=t$

Differentiating on both sides we get,

$-4 d x=d t$

$d x=-\frac{1}{4} d t$

substituting it in $\int \sec ^{2}(7-4 x) d x$ we get,

$=\int-\frac{1}{4} \sec ^{2} t d t$

$=\tan t+c$

$=\tan (7-4 x)+c$

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now