Evaluate the following limits:

Question:

Evaluate the following limits:

$\lim _{x \rightarrow 0} \frac{a x+x \cos x}{b \sin x}$

 

Solution:

$=\lim _{x \rightarrow 0} \frac{a x+x \cos x}{b \sin x}$

$=\lim _{x \rightarrow 0} \frac{a x}{b \sin x}+\frac{x \cos x}{b \sin x}$

$=\lim _{x \rightarrow 0} \frac{a x}{b \sin x}+\lim _{x \rightarrow 0} \frac{x \cos x}{b \sin x}$

$\left.=\frac{a}{b}+\frac{1}{b}\left[\because \lim _{\theta \rightarrow 0} \frac{\sin \theta}{\theta}=1\right]_{x \rightarrow 0} \cos \theta=1\right]$

$=\frac{a+1}{b}$

$\therefore \lim _{x \rightarrow 0} \frac{a x+x \cos x}{b \sin x}=\frac{a+1}{b}$

 

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