Factorise:

Question:

Factorise:
x2 − x(a + 2b) + 2ab

Solution:

We have:

$x^{2}-x(a+2 b)+2 a b=x^{2}-a x-2 b x+2 a b$

$=x^{2}-2 b x-a x+2 a b$

$=\left(x^{2}-2 b x\right)-(a x-2 a b)$

$=x(x-2 b)-a(x-2 b)$

$=(x-2 b)(x-a)$

$\therefore x^{2}-x(a+2 b)+2 a b=(x-2 b)(x-a)$

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