Factorise
$1-27 a^{3}$
$1-27 a^{3}=1^{3}-(3 a)^{3}$
$=(1-3 a)\left[1^{2}+1 \times 3 x+(3 a)^{2}\right]$
$=(1-3 a)\left(1+3 a+9 a^{2}\right)$
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