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Find out the oxidation number of chlorine

Question:

Find out the oxidation number of chlorine in the following compounds and arrange them in increasing order of oxidation number of chlorine.

NaClO4, NaClO3, NaClO, KClO2, Cl2O7, ClO3, Cl2O, NaCl, Cl2, ClO2

Solution:

NaClO4 x= +7

NaClO3, x= +5

NaClO, x=+1

KClO2, x= +3

Cl2O7, x= +7

ClO3, x= +6

Cl2O, x=+1

NaCl, x=-1

Cl2, x=0

ClO2, x= +4

Ascending order of compounds w.r.t their oxidation number is:

NaCl (-1), Cl2(0), Cl2O(+1), KClO2(+3), ClO2(+4), NaClO3(+5), ClO3(+6), Cl2O7=NaClO4(+7).

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