Find the 7th term in the expansion


Find the 7 th term in the expansion of $\left(\frac{4 x}{5}+\frac{5}{2 x}\right)^{8}$.


We need to find the 7th term in the given expression.

$\because T_{7}=T_{6+1}$


$\therefore T_{7}=T_{6+1}$

$={ }^{8} C_{6}\left(\frac{4 x}{5}\right)^{8-6}\left(\frac{5}{2 x}\right)^{6}$

$=\frac{8 \times 7 \times 4 \times 4 \times 125 \times 125}{2 \times 1 \times 25 \times 64} x^{2}\left(\frac{1}{x^{6}}\right)$


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