Find the 8th term in the expansion

Question:

Find the 8th term in the expansion of $\left(x^{3 / 2} y^{1 / 2}-x^{1 / 2} y^{3 / 2}\right)^{10} .$

Solution:

We need to find the 8th term in the given expression.

$\because T_{8}=T_{7+1}$

$\therefore T_{8}={ }^{10} C_{7}\left(x^{3 / 2} y^{1 / 2}\right)^{10-7}\left(-x^{1 / 2} y^{3 / 2}\right)^{7}$

$=-\frac{10 \times 9 \times 8}{3 \times 2} x^{9 / 2} y^{3 / 2}\left(x^{7 / 2} y^{21 / 2}\right.$)

$=-120 x^{8} y^{12}$

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now