# Find the A.M. between:

Question:

Find the A.M. between:

(i) 7 and 13

(ii) 12 and −8

(iii) (x − y) and (x + y).

Solution:

(i) Let $A_{1}$ be the A.M. between 7 and $13 .$

$A_{1}=\frac{a+b}{2}$

$=\frac{7+13}{2}$

= 10

(ii) Let $A_{1}$ be the A.M. between 12 and $-8$.

$A_{1}=\frac{a+b}{2}$

$=\frac{12+(-8)}{2}$

=2

(iii) Let $A_{1}$ be the A.M. between $(x-y)$ and $(x+y)$.

$A_{1}=\frac{a+b}{2}$

$=\frac{(x-y)+(x+y)}{2}$

$=x$