Question:
Find the angle subtended at the centre of a circle of radius 'a' by an arc of length (aπ/4) cm.
Solution:
We know that the arc length l of a sector of an angle θ in a circle of radius r is
$l=\frac{\theta}{360^{\circ}} \times 2 \pi r$
It is given $l=\frac{a \pi}{4} \mathrm{~cm}$ and radius $r=a \mathrm{~cm}$.
Now we substitute the value of l and r in above formula to find the value of angle θ subtended at the centre of circle.
$\frac{a \pi}{4} \mathrm{~cm}=\frac{\theta}{360^{\circ}} \times 2 \pi \times a$
$\theta=\frac{a \pi \times 360^{\circ}}{2 \pi a \times 4}$
$\theta=45^{\circ}$