Question:
Find the circumference of a circle whose area is 301.84 cm2.
Solution:
Let r cm be the radius of the circle. Then
Area of a circle is
$A=\pi r^{2} \mathrm{~cm}^{2}$
$301.84 \mathrm{~cm}^{2}=\pi \times r^{2}$
$301.84 \mathrm{~cm}^{2}=\frac{22}{7} \times r^{2}$
$r^{2}=96.04 \mathrm{~cm}^{2}$
$r=9.8 \mathrm{~cm}$
We know that the Circumference of circle of radius r is
$C=2 \pi r \mathrm{~cm}$
So substituting the value of r in above formula
$C=2 \times \frac{22}{7} \times 9.8 \mathrm{~cm}$
$=61.6 \mathrm{~cm}$