Question:
Find the discriminant of the quadratic equation $3 \sqrt{3} x^{2}+10 x+\sqrt{3}=0$.
Solution:
Given that quadric equation is $3 \sqrt{3} x^{2}+10 x+\sqrt{3}=0$.
Then, find the value of discrimenant.
Here, $a=3 \sqrt{3}, b=10$ and, $c=\sqrt{3}$
As we know that discrimenant $D=b^{2}-4 a c$
Putting the value of $a=3 \sqrt{3}, b=10$ and,$c=\sqrt{3}$
$=(10)^{2}-4 \times 3 \sqrt{3} \times \sqrt{3}$
$=100-36$
$=64$
Thus, the value of discrimenant be $\mathrm{D}=64$.
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