Find the discriminant of the quadratic equation

Given that quadric equation is $3 \sqrt{3} x^{2}+10 x+\sqrt{3}=0$.

Then, find the value of discrimenant.

Here, $a=3 \sqrt{3}, b=10$ and, $c=\sqrt{3}$

As we know that discrimenant $D=b^{2}-4 a c$

Putting the value of $a=3 \sqrt{3}, b=10$ and,$c=\sqrt{3}$

$=(10)^{2}-4 \times 3 \sqrt{3} \times \sqrt{3}$

$=100-36$

$=64$

Thus, the value of discrimenant be $\mathrm{D}=64$.