Find the equation of the line which passes through the point

We know that the equation of the line passing through point $\left(x_{0}, y_{0}\right)$, whose slope is $m$, is $\left(y-y_{0}\right)=m\left(x-x_{0}\right)$.

Thus, the equation of the line passing through point $(-4,3)$, whose slope is $\frac{1}{2}$, is

$(y-3)=\frac{1}{2}(x+4)$

$2(y-3)=x+4$

$2 y-6=x+4$

i.e., $x-2 y+10=0$