Find the least number which when divided by 35, 56 and 91 leaves the same remainder

Question:

Find the least number which when divided by 35, 56 and 91 leaves the same remainder 7 in each case.

Solution:

Least number which can be divided by 35, 56 and 91 is LCM of 35, 56 and 91.

Prime factorization of 35, 56 and 91 is:

35 = 5 × 7

$56=2^{3} \times 7$

91 = 7 × 13

LCM = product of greatest power of each prime factor involved in the numbers $=2^{3} \times 5 \times 7 \times 13=3640$

Least number which can be divided by 35, 56 and 91 is 3640.

Least number which when divided by 35, 56 and 91 leaves the same remainder 7 is 3640 + 7 = 3647.

Thus, the required number is 3647.

 

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Javier Yeager
Feb. 11, 2023, 12:26 p.m.
To the esaral.com webmaster, Great post!
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