Find the maximum number of students among whom 1001 pens and 910

Question:

Find the maximum number of students among whom 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and the same number of pencils.

Solution:

Total number of pens = 1001
Total number of pencils = 910
∴​ Maximum number of students who get the same number of pens and pencils = HCF (1001, 910)
Prime factorisation:

$1001=11 \times 91$

$910=10 \times 91$

$\therefore \mathrm{HCF}=91$

Hence, 91 students receive same number of pens and pencils.

 

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