Find the point on x-axis which is equidistant from points A(−1, 0) and B(5, 0).

Let P(x, 0) be the point on x-axis. Then

$A P=B P \Rightarrow A P^{2}=B P^{2}$

$\Rightarrow(x+1)^{2}+(0-0)^{2}=(x-5)^{2}+(0-0)^{2}$

$\Rightarrow x^{2}+2 x+1=x^{2}-10 x+25$

$\Rightarrow 12 x=24 \Rightarrow x=2$

Hence, x = 2.