Find the principal value of each of the following :
$\sin ^{-1}\left(\frac{-1}{2}\right)$
$\sin ^{-1}\left(\frac{-1}{2}\right)=-\sin ^{-1}\left(\frac{1}{2}\right)$ [Formula: $\sin ^{-1}(-x)=\sin ^{-1}(x)$ ]
$=-\frac{\pi}{6}$
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