Deepak Scored 45->99%ile with Bounce Back Crack Course. You can do it too!

Find the principal value of each of the following :

Question:

Find the principal value of each of the following :

$\sin \left\{\frac{\pi}{3}-\sin ^{-1}\left(\frac{-1}{2}\right)\right\}$

 

Solution:

$\sin \left\{\frac{\pi}{3}-\sin ^{-1}\left(\frac{-1}{2}\right)\right\}\left[\right.$ Formula: $\left.\sin ^{-1}(-x)=-\sin ^{-1} x\right]$

$=\sin \left\{\frac{\pi}{3}-\left(-\sin ^{-1} \frac{1}{2}\right)\right\}$

$=\sin \left\{\frac{\pi}{3}+\sin ^{-1}\left(\frac{1}{2}\right)\right\}$

Putting value of $\sin ^{-1}\left(\frac{1}{2}\right)$

$=\sin \left\{\frac{\pi}{3}+\frac{\pi}{6}\right\}$

$=\sin \frac{3 \pi}{6}$

$=\sin \frac{\pi}{2}$

$=1$

 

Leave a comment

None
Free Study Material