Find the product:

Question:

Find the product:
(3p2 + q2) × (2p2 − 3q2)

Solution:

By horizontal method:

$\left(3 p^{2}+q^{2}\right) \times\left(2 p^{2}-3 q^{2}\right)$

$=3 p^{2}\left(2 p^{2}-3 q^{2}\right)+q^{2}\left(2 p^{2}-3 q^{2}\right)$

$=6 p^{4}-9 p^{2} q^{2}+2 p^{2} q^{2}-3 q^{4}$

i. $e 6 p^{4}-7 p^{2} q^{2}-3 q^{4}$

 

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