Find the product:


Find the product:
(2x2 + 3x − 7) × (3x2 − 5x + 4)


By horizontal method:

$\left(2 x^{2}+3 x-7\right) \times\left(3 x^{2}-5 x+4\right)$

$=2 x^{2}\left(3 x^{2}-5 x+4\right)+3 x\left(3 x^{2}-5 x+4\right)-7\left(3 x^{2}-5 x+4\right)$

$=6 x^{4}-10 x^{3}+8 x^{2}+9 x^{3}-15 x^{2}+12 x-21 x^{2}+35 x-28$

$=6 x^{4}-x^{3}-28 x^{2}+47 x-28$


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