Find the value


Find the value

$8 x^{3}+y^{3}+12 x^{2} y+6 x y^{2}$



$=(2 x)^{3}+(y)^{3}+3 \times(2 x)^{2} \times y+3(2 x) \times y^{2}$

$=(2 x+y)^{3}$

$\left[\therefore a^{3}+b^{3}+3 a^{2} b+3 a b^{2}=(a+b)^{3}\right]$

$=(2 x+y)(2 x+y)(2 x+y)$

$\therefore 8 x^{3}+y^{3}+12 x^{2} y+6 x y^{2}=(2 x+y)(2 x+y)(2 x+y)$

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