find the value


If $10^{x}=64$, find the value of $10^{\left(\frac{x}{2}+1\right)}$



We have,


Taking square root from both sides, we get



$\Rightarrow 10^{\left(\frac{x}{2}\right)}=8$

Multiplying both sides by 10 , we get

$10^{\left(\frac{x}{2}\right)} \times 10=8 \times 10$

$\therefore 10^{\left(\frac{x}{2}+1\right)}=80$


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