Find the value

Solution:

Left Hand Limit(L.H.L.):

$\lim _{x \rightarrow 3^{-}} f(x)$

$=\lim _{x \rightarrow 3^{-}}|x|-3$

$=\lim _{x \rightarrow 3^{-}}-(x-3)$

$=-(3-3)$

$=0$

Right Hand Limit(R.H.L.):

$\lim _{x \rightarrow 3^{+}} f(x)$

$=\lim _{x \rightarrow 3^{+}}|x|-3$

$=\lim _{x \rightarrow 3^{+}}(x-3)$

$=3-3$

$=0$

Since,

$\lim _{x \rightarrow 3^{-}} f(x)=\lim _{x \rightarrow 3^{+}} f(x)$

We can say that the limit exists and

$\lim _{x \rightarrow 3} f(x)=0$