Find the value of x for which the points


Find the value of $x$ for which the points $A(x, 2), B(-3,-4)$ and $C(7,-5)$ are collinear.



Let $A\left(x_{1}, y_{1}\right)=A(x, 2), B\left(x_{2}, y_{2}\right)=B(-3,-4)$ and $C\left(x_{3}, y_{3}\right)=C(7,-5)$. So, the condition for three collinear points is


$\Rightarrow x(-4+5)-3(-5-2)+7(2+4)=0$

$\Rightarrow x+21+42=0$

$\Rightarrow x=-63$

Hence, x = − 63.


Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now