For a d4 metal ion in an octahedral field,

eSaral Updated on:
Question:

For a $\mathrm{d}^{4}$ metal ion in an octahedral field, the correct electronic configuration is :

  1. $\mathrm{t}_{2 \mathrm{~g}}^{4} \mathrm{e}_{\mathrm{g}}^{0}$ when $\Delta_{\mathrm{O}}<\mathrm{P}$

  2. $\mathrm{e}_{\mathrm{g}}^{2} \mathrm{t}_{2 \mathrm{~g}}^{2}$ when $\Delta_{\mathrm{O}}<\mathrm{P}$

  3. $\mathrm{t}_{2 \mathrm{~g}}^{3} \mathrm{e}_{\mathrm{g}}^{1}$ when $\Delta_{\mathrm{O}}<\mathrm{P}$

  4. $\mathrm{t}_{2 \mathrm{~g}}^{3} \mathrm{e}_{\mathrm{g}}^{1}$ when $\Delta_{\mathrm{O}}>\mathrm{P}$

Correct Option: , 3

Solution:

back pairing is not possible because pairing energy

$>\Delta_{\mathrm{O}}$

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