For a reaction scheme


For a reaction scheme $\mathrm{A} \stackrel{k_{1}}{\longrightarrow} \mathrm{B} \stackrel{k_{2}}{\longrightarrow} \mathrm{C}$, if the rate of formation of $B$ is set to be zero then the concentration of $B$ is given by:

  1. $\left(k_{1}-k_{2}\right)[\mathrm{A}]$

  2. $k_{1} k_{2}[\mathrm{~A}]$

  3. $\left(k_{1}+k_{2}\right)[\mathrm{A}]$

  4. $\left(\frac{k_{1}}{k_{2}}\right)[\mathrm{A}]$

Correct Option: , 4


$\mathrm{A} \stackrel{\mathrm{k}_{1}}{\longrightarrow} \mathrm{B} \stackrel{\mathrm{k}_{2}}{\longrightarrow} \mathrm{C}$



Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now