For VHF signal broadcasting,

Question:

For VHF signal broadcasting, $\mathrm{km}^{2}$ of maximum service area will be covered by an antenna tower of height $30 \mathrm{~m}$, if the receiving antenna is placed at ground. Let radius of the earth be $6400 \mathrm{~km}$. (Round off to the Nearest Integer) (Take $\pi$ as $3.14$ )

Solution:

$(1206)$

$d=\sqrt{2 R h}$

$\mathrm{~A}=\pi \mathrm{d}^{2}$

$\mathrm{~A}=\pi 2 \mathrm{Rh}$

$=3.14 \times 2 \times 6400 \times \frac{30}{1000}$

$\mathrm{A}=1205.76 \mathrm{~km}^{2}$

$\mathrm{~A}=1206 \mathrm{~km}^{2}$

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