Given the function

Question:

Given the function $f(x)=\frac{1}{x+2}$. Find the points of discontinuity of the function $f(f(x))$.

Solution:

$f[f(x)]=\frac{1}{\frac{1}{x+2}+2}=\frac{x+2}{2 x+5}$

So, $f[f(x)]$ is not defined at $x+2=0$ and $2 x+5=0$

If $x+2=$, then $x=-2$

If $2 x+5=0$, then $x=-\frac{5}{2}$

Hence, the function is discontinuous at $x=-\frac{5}{2}$ and $-2$

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now