How do you explain the presence


How do you explain the presence of five —OH groups in the glucose molecule?


When glucose is treated with acetic anhydride (CH3CO)2O, in the presence of ZnCl2, it undergoes acetylation to form glucose pentaacetate which confirms the presence of five –OH groups.

Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now