How many persons can be accommodated in a dining hall of dimensions (20 m × 16 m × 4.5 m),

Question:

How many persons can be accommodated in a dining hall of dimensions (20 m × 16 m × 4.5 m), assuming that each person requires 5 cubic metres of air?

Solution:

Volume of the dining hall $=(20 \times 16 \times 4.5) \mathrm{m}^{3}$

$=1440 \mathrm{~m}^{3}$

Volume of air required by each person $=5 \mathrm{~m}^{3}$

$\therefore$ Capacity of the dining hall $=\frac{\text { volume of dining hall }}{\text { volume of air required by each person }}=\frac{1440}{5}=288$ persons

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