**Question:**

**(i) In the explanation of the photoelectric effect, we assume one photon of frequency ν collides with an electron and transfers its energy. This leads to the **

**equation for the maximum energy Emax of the emitted electron as Emax = hν – φ0 where φ0 is the work function of the metal. If an electron absorbs 2 photons **

**(each of frequency ν ) what will be the maximum energy for the emitted electron?**

**(ii) Why is this fact (two-photon absorption) not taken into consideration in our discussion of the stopping potential?**

**Solution:**

(i) From the question, the energy absorbed by the electron is two protons with frequency v and v’= 2v where v’ is the frequency from the emitted electron.

Emax = hv – ϕ0

(ii) The emission is negligible as the chances of the same proton absorbing the energy is very low.

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