If 53x = 125 and 10y

Question:

If $5^{3 x}=125$ and $10^{y}=0.001 .$ Find $x$ and $y .$

Solution:

$5^{3 x}=125$ and $10^{y}=0.001$

$5^{3 x}=5^{3}$

$x=1$

Now,

$10^{\mathrm{y}}=0.001$

$10^{\mathrm{y}}=10^{-3}$

$\mathrm{y}=-3$

Therefore, the value of x = 1 and the value of y = – 3

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