If a + b + c = 0, then


If $a+b+c=0$, then $\left(\frac{a^{2}}{b c}+\frac{b^{2}}{c a}+\frac{c^{2}}{a b}\right)=?$



(d) 3
$a+b+c=0 \Rightarrow a^{3}+b^{3}+c^{3}=3 a b c$

Thus, we have:

$\left(\frac{a^{2}}{b c}+\frac{b^{2}}{c a}+\frac{c^{2}}{a b}\right)=\frac{a^{3}+b^{3}+c^{3}}{a b c}$

$=\frac{3 a b c}{a b c}$







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