Question:
If a matrix has 18 elements, what are the possible orders it can have?
Solution:
Number of entries $=$ (Number of rows) $\times$ (Number of columns) $=18$
If order is $(a \times b)$ then, Number of entries $=a \times b$
So now $\mathrm{a} \times \mathrm{b}=18$ (in this case)
Possible cases are $(1 \times 18),(2 \times 9),(3 \times 6),(6 \times 3),(9 \times 2),(18 \times 1)$
Conclusion: If a matrix has 18 elements, then possible orders are $(1 \times 18),(2 \times 9),(3 \times 6),(6 \times 3),(9 \times 2),(18 \times 1)$
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